Maclaurin and Taylor series: Find the indicated Maclaurin or Taylor series for the given function about the indicated point, and find the radius of convergence for the series.ex,x0=1

Short Answer

Expert verified

e+e(x-1)+e2!(x-1)2+e3!(x-1)3+e4!(x-1)4+orPn(x)=k=0ek!(x-1)k

Step by step solution

01

Given information

ex,x0=1

02

Concept

The formula used:Pn(x)=k=0fkx0k!x-x0n

03

Calculation

Consider the function f(x)=ex

Since for any function f with a derivative of order n the Taylor series at x=1 is given by

Pn(x)=f(1)+f'(1)(x-1)+f''(1)2!(x-1)2+f''(1)3!(x-1)3+f'''(1)4!(x-1)4+

Therefore, first, find the value of the function along with f'(x),f''(x),f''(x) and f''''(x) at x=1

Also, the general of the Taylor series of the function f is

Pn(x)=k=0fkx0k!x-x0n
04

Calculation

So, let's start by constructing the Taylor series table for the functionf(x)=exat x=1

As result, For the function, the Taylor seriesf(x)=exx=1is

e+e(x-1)+e2!(x-1)2+e3!(x-1)3+e4!(x-1)4+

We can also write it as

Pn(x)=k=0ek!(x-1)k

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