Show that when you take the derivative of the Maclaurin series for the exponential function term by term, you obtain the same series you started with. Why does that make sense?

Short Answer

Expert verified

The Maclaurin series derivate for the exponential function term by term is the same series as before.

Step by step solution

01

Step 1. Given information

The function isf(x)=ex

02

Step 2. Calculation

Let us consider the functionf(x)=ex

For function, the Maclaurin series is as follows:

ex=k=01k!x2k

The derivative of the functionfxis

f'(x)=ddxk=01k!xk=k=01k!ddx(x)k=k=01k!k·xk-1=k=01(k-1)!xk-1

It can also be written as:

f'(x)=0+1+x+x22!+x33!

Therefore, the Maclaurin series derivate for the exponential function term by term is the same series as before.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free