You were asked to find the Taylor series for the specified function at the given value of x0. In Exercises 45-50 find the Lagrange's form for the remainder Rn(x), and show that limnRn(x)=0on the specified interval.

x,1,(1/2,3/2)

Short Answer

Expert verified

The required Lagrange's form for the given remainder is,Rn(x)=x-π(n+1)!n+1

Step by step solution

01

Step 1. Given Information

The function isf(x)=x

02

. Calculation

If f(x)=x, we know that for every n0,f(n+1)(c)1for every value of x, so using the Lagrange's form for the remainder, we have

Rn(x)=f(n+1)(c)(n+1)!xn+1

03

Step 3. Simplification

Since the Taylor series for the function f(x)=xat x=1is

localid="1649858569361" Pn(x)=1+12(x-1)+k=2(-1)k+1k.1.3.5...(2k-3)2kk!(x-1)k

Therefore,Rn(x)=x-π(n+1)!n+1

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