You were asked to find the Taylor series for the specified function at the given value of x0. In Exercises 45-50 find the Lagrange's form for the remainder Rn(x), and show that limnRn(x)=0on the specified interval.

localid="1649857668603" lnx,3,(2,4)

Short Answer

Expert verified

The Lagrange's form for the remainderRn(x) on the specified interval is Rn(x)=1(n+1)cn+1(x-3)n+1

Step by step solution

01

Step 1. Given Information

The function is, f(x)=lnx

Phow that limnRn(x)=0on the specified interval.

02

Step 2. Calculation

If f(x)=lnx, we know that for every n0,fn+1(c)1, for every value of x, so using the Lagrange's form for the remainder, we have

Rn(x)=f(n+1)(c)(n+1)!(x-x0)n+1

03

Step 3. Simplification

Since the Taylor series for the function f(x)=lnx, at x=3is

Pn(x)=1+12(x-1)+k=2(-1)k+11.2.3...(k-1)3kk!(x-3)k

Therefore,Rn(x)=1(n+1)cn+1(x-3)n+1

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