Find the Maclaurin series for the specified function:

sinx.

Short Answer

Expert verified

The Maclaurin series is,

f(x)=k=0(-1)k(2k+1)!x2k+1.

Step by step solution

01

Step 1. Given Information.

The function is,

sinx.

02

Step 2. Formulae for the Maclaurin series.

Let f(x)=sinx.

Since, for any function fwith derivatives of all orders at the point x0=0then the Maclaurin series is,

f(x)=f(0)+f'(0)x+f''(0)2!x2+f'''(0)3!x3+.........

Or, we can write the general form Maclaurin series of the function fis,

localid="1649653268867">f(x)=n=0fn(0)n!xn.

03

Step 3. Finding the Maclaurin series.

So, let us first construct the table of the Maclaurin series for the function f(x)=sinx,

Therefore the Maclaurin series for the functionf(x)=sinxis,

0+1.x+02!x2+(-1)3!x3+0x4+15!x5+06!x6+......

Or, we can write as,

f(x)=k=0(-1)k(2k+1)!x2k+1.

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