If limkakbk=andk=1ak diverges, explain why we cannot draw any conclusions about the behavior ofk=1bk.

Short Answer

Expert verified

Thebehavioroftheseriesbkk=1cannotbedeterminedwhenlimkakbk=andakk=1isdivergentholdsbecausetheseriesakk=1mayormaynotbedivergent,eventhoughlimkakbk=holds.

Step by step solution

01

Step 1. Given information

limkakbk=andk=1akdiverges

02

Step 2. Finding the value of limit 

Consider the convergent series k=1ak=k=11kand the series k=1bk=1k2.

Thevalueoflimkakbkis:limkakbk=limk1k1k2=limkk=

03

Step 3. Result

Theseriesbkk=1=1k2isconvergentbuttheseriesakk=1=1kisdivergent.Thebehavioroftheseriesbkk=1cannotbedeterminedwhenlimkakbk=andakk=1isdivergentholdsbecausetheseriesakk=1mayormaynotbedivergent,eventhoughlimkakbk=holds.

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Most popular questions from this chapter

True/False:

Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: If ak0, then k=1akconverges.

(b) True or False: If k=1akconverges, then ak0.

(c) True or False: The improper integral 1f(x)dxconverges if and only if the series k=1f(k)converges.

(d) True or False: The harmonic series converges.

(e) True or False: If p>1, the series k=1k-pconverges.

(f) True or False: If f(x)0as x, then k=1f(k) converges.

(g) True or False: If k=1f(k)converges, then f(x)0as x.

(h) True or False: If k=1ak=Land {Sn}is the sequence of partial sums for the series, then the sequence of remainders {L-Sn}converges to 0.

Let αbe any real number. Show that there is a rearrangement of the terms of the alternating harmonic series that converges to α. (Hint: Argue that if you add up some finite number of the terms of k=112k1, the sum will be greater than α. Then argue that, by adding in some other finite number of the terms of

k=112k , you can get the sum to be less than α. By alternately adding terms from these two divergent series as described in the preceding two steps, explain why the sequence of partial sums you are constructing will converge to α.)

Explain how you could adapt the integral test to analyze a series k=1f(k)in which the functionf:[1,) is continuous, negative, and increasing.

Find the values of x for which the series k=0cosx2kconverges.

An Improper Integral and Infinite Series: Sketch the function f(x)=1xfor x ≥ 1 together with the graph of the terms of the series k=11k.Argue that for every term Snof the sequence of partial sums for this series,Sn>1n+11xdx. What does this result tell you about the convergence of the series?

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