Use any convergence test from this section or the previous section to determine whether the series in Exercises 31–48 converge or diverge. Explain how the series meets the hypotheses of the test you select.

k=1k-4/3

Short Answer

Expert verified

The series k=1k-4/3is Convergent.

Step by step solution

01

Step 1. Given information 

We are given,

k=1k-4/3

02

Step 2. Checking the Convergence and Divergence

The terms of the series k=11k4/3are positive.

The series k=0bifor the series k=11k4/3is given by:

role="math" localid="1649243466348" k=0bk=k=01k4/3(Dominant term of numerator and denominator)

The ratio limkakbkis given by:

limkakbk=limk1k4/31k4/2(Substitution)=limk1=1

03

Step 3. Checking the Convergence and Divergence

The value of limkakbk=1; which is non-zero finite number.

The series k=0bk=k=01k4/3 is convergent by p-series test.

Therefore, the series k=0akis also convergent.

Hence, the series k=11k4/3is convergent

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