Use the ratio test for absolute convergence to determine whether the series in Exercises 30–35 converge absolutely or diverge.
k=0(-7)k(2k+1)!

Short Answer

Expert verified

The series k=0(-7)k(2k+1)!converges absolutely.

Step by step solution

01

Step 1. Given Information.

The series:

k=0(-7)k(2k+1)!

02

Step 2. Rewrite the series.

ak=(-7)k(2k+1)!

03

Step 3. Find ak+1.

ak+1=(-7)k+1(2(k+1)+1)!=(-7)k+1(2k+2+1)!=(-7)k+1(2k+3)!

04

Step 4. Calculate ak+1ak.

ak+1ak=(-7)k+1(2k+3)!(-7)k(2k+1)!=(-7)k+1(2k+1)!(-7)k(2k+3)!=-7(-7)k(2k+1)!(-7)k(2k+3)(2k+2)(2k+1)!=-7(2k+3)(2k+2)=72(2k+3)(k+1)

05

Step 5. Take limits.

limkak+1ak=limk72(2k+3)(k+1)=0

So by the ratio test, the series converges absolutely.

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