In Exercises 4–11, give examples of sequences satisfying the given conditions or explain why such an example cannot exist.
Two divergent sequences {ak}and {bk}such that the sequence {akbk}diverges.

Short Answer

Expert verified

The example of the sequence is {ak}={k2}and {bk}=k.

Step by step solution

01

Step 1. Given Information.

Two divergent sequence {ak}and{bk}.

02

Step 2. Consider the divergent sequence.

Consider the sequence {ak}={k2}which is strictly increasing and not bounded above.

So it is divergent sequence.

Consider the sequence {bk}={k}which is strictly increasing and not bounded above.

So it is divergent sequence.

03

Step 3. Division of the sequence.

The sequence {akbk}={k}which is a decreasing sequence and not bounded above.

And the sequence does not converge to zero.

So the division of two divergent sequence can be divergent.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free