Prove that ifakk=1 is a sequence of positive real numbers, then the sequence Snn=1, where the sequence Sn = a1 + a2 +···+an, is an increasing sequence.

Short Answer

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Proved.

Step by step solution

01

Step 1. Given

Consider the sequencesakk=1.

02

Step 2. Proof

ThesequenceSn=a1+a2+a3+...+an......(1)Changenton+1inequation(1)Sn+1=a1+a2+a3+...+an+an+1.....(2)Subtract(1)from(2)Sn+1-Sn=a1+a2+a3+...+an+an+1-(a1+a2+a3+...+an)=a.HenceSn+1-Sn=an+1SinceSn+1SnHencethesequenceisincreasingsequence.

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Most popular questions from this chapter

True/False:

Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: If ak0, then k=1akconverges.

(b) True or False: If k=1akconverges, then ak0.

(c) True or False: The improper integral 1f(x)dxconverges if and only if the series k=1f(k)converges.

(d) True or False: The harmonic series converges.

(e) True or False: If p>1, the series k=1k-pconverges.

(f) True or False: If f(x)0as x, then k=1f(k) converges.

(g) True or False: If k=1f(k)converges, then f(x)0as x.

(h) True or False: If k=1ak=Land {Sn}is the sequence of partial sums for the series, then the sequence of remainders {L-Sn}converges to 0.

Let f(x) be a function that is continuous, positive, and decreasing on the interval [1,)such that role="math" localid="1649081384626" limxf(x)=α>0. What can the divergence test tell us about the series k=1f(k)?

Which p-series converge and which diverge?

Prove Theorem 7.31. That is, show that if a function a is continuous, positive, and decreasing, and if the improper integral 1a(x)dxconverges, then the nth remainder, Rn, for the seriesk=1a(k) is bounded by0Rn=k=n+1a(k)na(x)dx

Examples: Construct examples of the thing(s) described in the following. Try to find examples that are different than any in the reading.

(a) A divergent series k=1akin which ak0.

(b) A divergent p-series.

(c) A convergent p-series.

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