Complete the square for each quadratic in Exercises 28–33. Then describe the trigonometric substitution that would be appropriate if you were solving an integral that involved that quadratic.

x2+6x2

Short Answer

Expert verified

The completing square of the given quadratic equation is x+32-11, and the appropriate trigonometric substitution isx+3=11secu.

Step by step solution

01

Step 1. Given Information.

The given quadratic isx2+6x-2.

02

Step 2. Completing the square for the given quadratic.

The complete square of the given quadratic equation is as follows:

x2+6x-2=x2+6x+32-2-32=x+32-11

03

Step 3. Describing the trigonometric substitution. 

After completing the square for the given quadratic equation it is in the form of x2-a2.

So, for solving an integral that involved the quadratic then the trigonometric substitution can be used islocalid="1649054533258" x=asecu.

Here,x=x+3,a=11.

Thus, the appropriate trigonometric substitution islocalid="1649054515691" x+3=11secu.

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