Calculate each definite integral approximation in Exercises 23–40, and then find an error bound for your approximation. If it is possible to calculate the definite integral exactly, then do so and verify that the error bounds you found are accurate

17ln(x)dx,trapezoidsum,n=12

Short Answer

Expert verified

Definite integral is 7.6213

Error <=0.125

Step by step solution

01

Given Information 

17ln(x)dx,trapezoidsum,n=12

02

Definite integral 

17ln(x)dxxlnx-x177ln7-7-1ln1-1thevalueofdefinteintegralis7.6213

03

Trapezoidal sum 

abf(x)dx=x2f(x_0)+2f(x1)+2f(x2).....+f(xn)x=b-an=7-112=14leftendpointofIntervalsare1,32,2,52,3,72,4,92,5,112,6,132,7f(x)=ln(x)Substituteeachendpointandfindotuthesumsum=14ln(1)+2ln(32)+2ln(2)+2ln(52)+2ln(3)+2ln(72)+2ln(4)+2ln(92)+2ln(5)+2ln(112)+2ln(6)+2ln(132)+ln7sum=7.603676

04

Error 

f(x)=ln(x)f'(x)=1xf''(x)=-1x2f''(x)isnegativesoitisconcavedownwardontheinterval[1,3]M=f''(x)|=|-1x2||-112|1|E|M(b-a)312n2|E|1(7-1)312(12)20.125Actualareais7.6213iswithintheerrorboundofapproximatevalue

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