Chapter 5: Q. 49 (page 442)

Calculate each of the definite integrals in Exercises 47–52. Some integrals require partial fractions or polynomial long division, and some do not.
$\int_{1}^{3} \frac{1}{x (x + 1)} d x$

Short Answer

Expert verified

The value is $\ln (3) - \ln (2)$

Step by step solution

Step 1. Given Information:

Given definite integral : $\int_{1}^{3} \frac{1}{x (x + 1)} d x$

We want to calculate each of the definite integrals.

Step 2. Calculation:

Use partial fraction we get:

$\frac{1}{x (x + 1)} = \frac{A}{x} + \frac{B}{x + 1} 1 = A (x + 1) + B x C o m p a r e t h e c o e f f i c i e n t w e g e t 1 = A a n d 0 = A + B 1 = A a n d - 1 = B Use these values we get : \frac{1}{x (x + 1)} = \frac{1}{x} - \frac{1}{x + 1} Now \int_{1}^{3} \frac{1}{x (x + 1)} d x = \int_{1}^{3} \frac{1}{x} d x - \int_{1}^{3} \frac{1}{x + 1} d x = \ln | x |_{1}^{3} - \ln | x + 1 |_{1}^{3} = \ln (3) - \ln (1) - (\ln (4) - \ln (2)) U \sin g \log p r o p e r t i e s : = \ln (3) - \ln (2)$

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Calculate each of the definite integrals in Exercises 47–52. Some integrals require partial fractions or polynomial long division, and some do not.
$\int_{1}^{3} \frac{1}{x (x + 1)} d x$

Short Answer

Step by step solution

Step 1. Given Information:

Step 2. Calculation:

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Calculate each of the definite integrals in Exercises 47–52. Some integrals require partial fractions or polynomial long division, and some do not.∫131x(x+1)dx

Short Answer

Step by step solution

Step 1. Given Information:

Step 2. Calculation:

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Statistics

Mechanics Maths

Applied Mathematics

Theoretical and Mathematical Physics

Logic and Functions

Discrete Mathematics

Study anywhere. Anytime. Across all devices.

Calculate each of the definite integrals in Exercises 47–52. Some integrals require partial fractions or polynomial long division, and some do not.
$\int_{1}^{3} \frac{1}{x (x + 1)} d x$