Solve each of the integrals in Exercises 27–70. Some integrals require integration by parts, and some do not. (The last two exercises involve hyperbolic functions.)

x3sinx2dx

Short Answer

Expert verified

The value is-x22cosx2+12sinx2+C.

Step by step solution

01

Step 1. Given information.

The given integral isx3sinx2dx.

02

Step 2. Substitution.

Now,

u=x2du=2xdxx3sinx2dx=u2sin(u)du=12usin(u)du

03

Step 3. Value of the integral.

Again,

letw=u,dv=sinx2dx.dv=sin2xdxv=x2-14sin2xNow,12usin(u)du=12(u(-cosu))-(-cosu)du=12(-ucosu)+cosudu=-u2cosu+12cosudu=-u2cosu+12sinu=-x22cosx2+12sinx2+C

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Most popular questions from this chapter

Find three integrals in Exercises 27–70 for which either algebra or u-substitution is a better strategy than integration by parts.

Find three integrals in Exercises 39–74 that can be solved without using trigonometric substitution.

True/False: Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The substitution x = 2 sec u is a suitable choice for solving1x24dx.

(b) True or False: The substitution x = 2 sec u is a suitable choice for solving1x24dx.

(c) True or False: The substitution x = 2 tan u is a suitable choice for solving1x2+4dx.

(d) True or False: The substitution x = 2 sin u is a suitable choice for solvingx2+45/2dx

(e) True or False: Trigonometric substitution is a useful strategy for solving any integral that involves an expression of the form x2a2.

(f) True or False: Trigonometric substitution doesn’t solve an integral; rather, it helps you rewrite integrals as ones that are easier to solve by other methods.

(g) True or False: When using trigonometric substitution with x=asinu, we must consider the cases x>a and x<-a separately.

(h) True or False: When using trigonometric substitution with x=asecu, we must consider the cases x>a and x<-a separately.

Solve the integralx3x2-1dxthree ways:

(a) with the substitution u=x2-1,followed by back substitution;

(b) with integration by parts, choosing localid="1648814744993" u=x2anddv=xx2-1dx;

(c) with the trigonometric substitution x = sec u.

Solve the integral:xexdx

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