Solve the definite integral.

π4π2xcsc2xdx

Short Answer

Expert verified

The solution is14π+2log2.

Step by step solution

01

Step 1. Given information.

The given integral isπ4π2xcsc2xdx.

02

Step 2. First, solve the indefinite integral.

I=xcsc2xdx=xcsc2xdx-ddx(x)csc2xdxdx=x(-cotx)-1(-cotx)dx=-xcotx+cotxdx=-xcotx+logsinxcotxdx=logsinx

03

Step 3. Now apply the limit of integration.

π4π2xcsc2xdx=-xcotx+logsinxπ4π2=-π2cotπ2+logsinπ2--π4cotπ4+logsinπ4=14π+2log2

04

Step 4. Simplified answer.

Hence, the required value is14π+2log2.

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