Solve the definite integration.

-1212sin-1xdx

Short Answer

Expert verified

The solution is0.

Step by step solution

01

Step 1. Given information.

The given integral is-1212sin-1xdx.

02

Step 2. First, solve the indefinite integral.

I=sin-1xdx=sin-1xdx-ddxsin-1xdxdx=sin-1x·x-11-x2·xdx=sin-1x·x-x1-x2dx=xsin-1x-I1

03

Step 3. Solve for I1.

I1=x1-x2dx

Let 1-x2=t, -2xdx=dtxdx=-12dt.

I1=-12tdt=-12t-12dt=-12t-12+1-12+1=-12t1212=-122t=-t=-1-x2

04

Step 4. Apply the limit of integration.

-1212sin-1x=xsin-1x+1-x2-1212=12sin-112+1-122--12sin-1-12+1--122=12sin-112+1-14--12sin-1-12+1-14=12sin-112+34--12sin-1-12+34=π12+32-π12-32=0

05

Step 5. Simplified answer

Hence, the required value is0.

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