Consider the function f(x)=lnx.

(a) Find the signed area between the graph of f(x)and the x-axis on 12,4shown in the figure next at the left.

(b) Find the area between the graph of f(x)and the graph of g(x)=1on 12,4shown in the figure next at the right.

Short Answer

Expert verified

Part (a). The solution is -72+12ln(2)+4ln(4).

Part (b). The solution is-7+12ln(2)+4ln(4).

Step by step solution

01

Part (a) Step 1. Given information.

The given function isf(x)=lnx.

02

Part (a) Step 2. Solve the definite integral ∫124lnx dx.

Apply integration by parts and solve.

124lnxdx=lnxdx-ddx(lnx)dxdx124=lnx·x-1x·xdx124=lnx·x-dx124=lnx·x-x124=4ln4-4-12ln12-12=-72+12ln(2)+4ln(4)

03

Part (b) Step 1. Given information.

The given function isf(x)=lnxandg(x)=1.

04

Part (b) Step 2. Find the area between the graph of f(x)=lnx and g(x)=1 on 12,4.

The area is calculated below.

124f(x)-g(x)dx=124lnx-1dx=124lnxdx-124dx=xlnx-x124-x124=-72+12ln(2)+4ln(4)-4-12=-72+12ln(2)+4ln(4)-72=-7+72+12ln(2)+4ln(4)=-7+12ln(2)+4ln(4)

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