Prove the integration formula cscxdx=ln|cscx+cotx|+C

(a) by multiplying the integrand by a form of 1 and then applying a substitution;

(b) by differentiating ln|cscx+cotx|.

Short Answer

Expert verified

(a) Formula is proved by multiplying the integrand by a form of 1 and then applying a substitution.

(b) Formula is proved by differentiating.

Step by step solution

01

Step 1. Given information

An integral iscscxdx=ln|cscx+cotx|+C

02

Part (a) Step 1. Explanation

cscxdx=cscxcscx+cotxcscx+cotxdx=csc2x+cscxcotxcscx+cotxdx

Let cscx+cotx=u

width="205">-cscxcotx-csc2xdx=du

cscxdx=-du=-u+C=-cscx-cotx+C

03

Part (b) Step 1. Explanation

ddx-lncscx+cotx=-1-csc2x-cscxcotxcscx+cotx=cscxcscxdx=-lncscx+cotx+C

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