We can extend the technique of trigonometric substitution to the hyperbolic functions. Use Theorem 2.20 and the identity ${\cosh }^{2}x-{\sinh }^{2}x=1$to solve each integral in Exercises 87– 90 with an appropriate hyperbolic substitution $x=a\sinh u\text{or}x=a\cosh u.$. (These exercises involve hyperbolic functions.)

$\int \frac{1}{\sqrt{x^2+4}}dx$

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