Q. Examples: Construct examples of the thing(s) described in the following. Try to find examples that are different than any in the reading.

(a) A smooth surface with a smooth boundary.

(b) A surface that is not smooth, but that has a smooth boundary.

(c) A surface that is smooth, but does not have a smooth boundary

Short Answer

Expert verified

Part (a). An example for a smooth surface with a smooth boundary is as follows: surface S is a part of z=4-x2-y2above the plane z=0.

Part (b) An example for a surface that is not smooth with a smooth boundary is as follows: Surface S is a part of z=x2+y2between 0and 1.

Part (c) An example for a surface that is smooth, but does not have a smooth boundary is as follows: Surface S is part of x+y+z=1that lies in the first octant.

Step by step solution

01

Part (a) Step 1. Given Information

The objective is to construct an example of the thing described as follows.

"A smooth surface with a smooth boundary."

02

Part (a) Step 2. Explanation

First, define the all terms of the thing in the above sentence:

A surface is smooth if it has a smooth parametrization, and a parametrization is smooth if it is differentiable.

If a curve which has derivatives of all orders at all points of the curve, this curve is called a smooth curve.

Consider a surface S is a part of z=4-x2-y2above the plane z=0.

The parametrization of this surface is,

r(u,v)=ucosv,usinv,4-u2

Notice that, it is differentiable, so this surface is smooth.

The boundary curve of this surface is 4-x2-y2=0or x2+y2=4, which is smooth.

Hence, an example for a smooth surface with a smooth boundary is as follows: surface S is a part of z=4-x2-y2above the plane z=0.

03

Part (b) Step 1. Given Information

The objective is to construct an example of the thing described as follows:

"A surface that is not smooth, but that has a smooth boundary."

04

Part (b) Step 2. Explanation

A cone with equation z=x2+y2between z=0and z=1is not smooth or piece-wise smooth surface

At the vertex the normal vector is 0, so this surface is not smooth or piece-wise smooth surface, The boundary curve of this cone isx2+y2=1 which is smooth.

Hence, an example for a surface that is not smooth with a smooth boundary is as follows:

Surface S is a part ofz=x2+y2 between 0 and 1.

05

Part (c) Step 1. Given Information

The objective is to construct an example of the thing described as follows:

"A surface that is smooth, but does not have a smooth boundary."

06

Part (c) Step 2. Explanation

A plane with equation x+y+z=1that lies in the first octant is a smooth surface.

The boundary curve of this plane is bounded by the lines x+y=1,x=0, and y=0.

So this boundary is a triangle, and so it is not smooth. Hence, an example for a surface that is smooth, but does not have a smooth boundary is as follows:

Surface S is part of x+y+z=1that lies in the first octant.

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Most popular questions from this chapter

True/False: Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The result of integrating a vector field over a surface is a vector.

(b) True or False: The result of integrating a function over a surface is a scalar.

(c) True or False: For a region R in thexy-plane,dS=dA.

(d) True or False: In computing Sf(x,y,z)dS, the direction of the normal vector is irrelevant.

(e) True or False: If f (x, y, z) is defined on an open region containing a smooth surface S, then Sf(x,y,z)dSmeasures the flow through S in the positive z direction determined by f (x, y, z).

(f) True or False: If F(x, y, z) is defined on an open region containing a smooth surface S , then SF(x,y,z).ndSmeasures the flow through S in the direction of n determined by the field F(x, y, z).

(g) True or False: In computing SF(x,y,z).ndS,the direction of the normal vector is irrelevant.

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ComputethedivergenceofthevectorfieldsinExercises1722.F(x,y,z)=sin-1(xy)i+ln(y+z)j+12x+3y+5z+1k

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