In Exercises 17–24, find a potential function for the given vector field.

F(x,y,z)=yzi+xzj+xyk

Short Answer

Expert verified

A potential function for the given vector field is f(x,y,z)=xyz.

Step by step solution

01

Step 1. Given Information

In given exercises we have to find a potential function for the given vector field.

F(x,y,z)=yzi+xzj+xyk

02

Step 2. Since F(x,y,z)=yzi+xzj+xyk

F(x,y,z)=(yz)dx+B+CF(x,y,z)=yzdx+B+CF(x,y,z)=yzx+α+B+CF(x,y,z)=xyz+α+B+C

where α is an arbitrary constant and B is the integral with respect to y of the terms in role="math" localid="1650473109511" F2(x,y,z) in which the factor x does not appear.

03

Step 3. In this case, that is all of F2(x,y,z), so

B=xzdyB=xzdyB=xzy+βB=xyz+β

whereβ is an arbitrary constant.

04

Step 4. Now finding C=∫xydz

C=xydzC=xyz+γ

whereγ is an arbitrary constant.

Setting the constants equal to zero since they do not affect the gradient of role="math" localid="1650473089885" f(x,y,z)

We have,

f(x,y,z)=xyz

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