ComputethecurlofthevectorfieldsinExercises2328.F(x,y,z)=sin-1(xy)i+ln(y+z)j+12x+3y+5z+1k

Short Answer

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curlF=-32x+3y+5z+12+1y+zi+22x+3y+5z+12j-x1-(xy)2k

Step by step solution

01

Step 1. Given information is: 

F(x,y,z)=sin-1(xy)i+ln(y+z)j+12x+3y+5z+1k

02

Step 2. Curl of vector field

Here,F(x,y,z)=sin-1(xy)i+ln(y+z)j+12x+3y+5z+1kComparethiswith,F(x,y,z)=f1(x,y,z)i+f2(x,y,z)j+f3(x,y,z)kThen,f1(x,y,z)=sin-1(xy),f2(x,y,z)=ln(y+z),f3(x,y,z)=12x+3y+5z+1Now,curlF=ijkxyzsin-1(xy)ln(y+z)12x+3y+5z+1=i12x+3y+5z+1y-ln(y+z)z+jsin-1(xy)z-12x+3y+5z+1x+kln(y+z)x-sin-1(xy)y=-32x+3y+5z+12+1y+zi+22x+3y+5z+12j-x1-(xy)2k

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