Explainwhywedonotneedtoexplicitlyusealimitinthedefinitionforthedefiniteintegralofavectorfunctionr(t)=x(t),y(t),z(t).

Short Answer

Expert verified

Avectorfunctionisintegrableontheinterval[a,b]ifeachofitscomponentfunctionsisintegrableon[a,b].Everycomponentfunctionr(t)isascalarfunctionwhichisdefined.Thelimitisalreadyinvolvedinthedefinitionfortheintegrabilityofascalarfunction[a,b].Hence,weneednotexplicitlyusealimitinthedefinitionforthedefiniteintegralofr(t).

Step by step solution

01

Step 1. Given information is

r(t)=x(t),y(t),z(t)

02

Step 2. Definition of integrabilti on the scalar function

Integrabilityofy=f(x)on[a,b]:Lety=f(x)beafunctiondefinedontheinterval[a,b].Thisfunctionisintegrableiflimnk=1f(xkn)xexistswherex=b-an,xk=a+kxandxkn=xk-1,xk

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Step 3. Result

Avectorfunctionisintegrableontheinterval[a,b]ifeachofitscomponentfunctionsisintegrableon[a,b].Everycomponentfunctionr(t)isascalarfunctionwhichisdefined.Thelimitisalreadyinvolvedinthedefinitionfortheintegrabilityofascalarfunction[a,b].Hence,weneednotexplicitlyusealimitinthedefinitionforthedefiniteintegralofr(t).

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