In Exercises 21–23 you are given a vector function rand a scalar function t=f(τ). Computedrdτin the following two ways:

(a) By using the chain rule drdτ=drdtdtdτ.

(b) By substituting t=f(τ)into the formula for r. Ensure that your two answers are consistent.

Short Answer

Expert verified

Part (a) The answer isdrdt=3-T2sinT3,T2cosT3,T2

Part (b) The value isdrdt=3-T2sinT3,T2cosT3,T2

The two answers are consistent, that is drdτ=3τ2sinτ3,τ2cosτ3,τ2

Step by step solution

01

Part (a) Step 1. Given data

The given vector function isr(t)=cost,sint,t,t=τ3

We have to find drdτin two ways,

02

Part (a) Step 2. Find drdτ

By using the chain rule,drdτ=drdtdtdτ

drdτ=ddtr(t)ddτ(t)=ddtcost,sint,tddτ(τ3)=sint,cost,1(3τ2)=sinτ3,cosτ3,1(3τ2)=3(τ2sinτ3,τ2cosτ3,τ2)

03

Part (b) Step 1. Find drdτ by substituting t=f(τ)

By substituting t=sinτin r(t)

r(t)=cost,sint,t=cosτ3,sinτ3,τ3drdτ=ddτr(t)=ddτcosτ3,sinτ3,τ3=3τ2sinτ3,3τ2cosτ2,3τ2=3τ2sinτ2,τ2cosτ2,τ2

Here, results obtained in part (a) and part (b) are equal.

Therefore, the two answers are consistent.

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