In Exercises 31–35 find the curvature of the given function at the indicated value of x. Then sketch the curve and the osculating circle at the indicated point.

y=ex,x=0

Short Answer

Expert verified

The curvature atx=0isk=24.

The graph is

Step by step solution

01

Step 1. Given information.

The given function and point isy=ex,x=0.

02

Step 2. Curvature at the point.

The curvature is given by,

k=f'(x)1+f'(x)232f'(x)=exf''(x)=exk=ex1+ex232k=ex1+e2x32Atx=0,k=e01+e2(0)32k=1232k=212232·212k=222k=24

03

Step 3. Graph.

The graph will be,

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