Given a differentiable vector-valued function r(t),explain why r'(t0) is tangent to the curve defined by r(t) when the initial point of r'(t0) is placed at the terminal point ofr'(t0)

Short Answer

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r'(t0)is a tangent to the curve defined by r(t)when the initial point of r'(t0)is placed at the terminal of r(t0)

Step by step solution

01

Step 1. Given information

The given a differentiable vector - valued function r(t)

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Step 2. The objective is to explain why r'(t0) is a tangent to the curve defined by r(t) when the initial point of r'(t0) is placed at the terminal point of r(t) .

For this the definition of the derivative of the vector - valued function should be considered first:
The Derivative of a vector - valued function:
Letr(t)be a differentiable vector function. Then the derivative ofr(t)is
r'(t)=limh0r(t+h)-r(t)hr'(t)=limh0r(t0+h)-r(t)h
Derivative ofr(t)consists ofr(t+h)-r(t)in the numerator, the difference of vector point from the terminal point ofr(t). Ifr'(t0)starts from the terminal point ofr(t)it becomes tangent to the curve.
Thus r'(t0)is a tangent to the curve defined by r(t)when the initial point of r'(t0)is placed at the terminal ofr(t0)

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