Chapter 11: Q. 60 (page 890)
Use Theorem 11.24 to prove that the curvature of a linear function y = mx + b is zero for every value of x.
Short Answer
It is proved thatthe curvature of a linear functiony = mx + b is zero for every value ofx.
Chapter 11: Q. 60 (page 890)
Use Theorem 11.24 to prove that the curvature of a linear function y = mx + b is zero for every value of x.
It is proved thatthe curvature of a linear functiony = mx + b is zero for every value ofx.
All the tools & learning materials you need for study success - in one app.
Get started for freeFor each of the vector-valued functions in Exercises , find the unit tangent vector and the principal unit normal vector at the specified value of t.
For each of the vector-valued functions, find the unit tangent vector.
Evaluate and simplify the indicated quantities in Exercises 35–41.
Let be a differentiable vector function on some interval such that the derivative of the unit tangent vector , where . Prove that the binormal vector
(a) is a unit vector;
(b)is orthogonal to both and .
Also, prove that , and form a right-handed coordinate system.
Find the unit tangent vector and the principal unit normal vector at the specified value of t.
What do you think about this solution?
We value your feedback to improve our textbook solutions.