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Chapter 10: Q 26 (page 849)

Find the value of $||v||, v = <0, - 3, 2>$

Short Answer

Expert verified

The required value of norm is $\sqrt{11}$ .

Step by step solution

01

Given information

A vector $v = <0, - 3, 2>$

02

Find the norm

The norm of given vector is:

$||v|| = \sqrt{0^{2} + {(- 3)}^{2} + 2^{2}}$

Simplify:

$||v|| = \sqrt{11}$

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Most popular questions from this chapter

Find a vector in the direction opposite to $<- 1, - 4, - 6>$ andwith magnitude 7.

Find $||v||$ and find the unit vector in the direction of $v$ .

$v = (3, - 4)$

If u and v are nonzero vectors in $ℝ^{3}$ , what is the geometric relationship between $u, v$ and $u \times v$ ?

In Exercises 22–29 compute the indicated quantities when $u = (2, 1, - 3), v = (4, 0, 1), and w = (- 2, 6, 5)$

$u \times v and v \times u$

Use calculator graphs to make approximations for each of the limits in Exercises 67–74.

$\lim_{x \to 4} (3 - 4 x - 5 x^{2})$

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