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Chapter 10: Q 32. (page 801)

Find $\vec{P Q}$
$P = (- 1, 5, 4), Q = (- 1, 6, 4)$

Short Answer

Expert verified

The required value of $\vec{P Q}$ is $(0, 1, 0)$ .

Step by step solution

01

Step 1. Given information .

We have given vector $P = (- 1, 5, 4) a n d Q = (- 1, 6, 4)$ .

02

Step 2. Find the values of PQ→.

$\vec{P Q} = (x_{2} - x_{1}, y_{2} - y_{1}, z_{2} - z_{1}) = (- 1 - (- 1), 6 - 5, 4 - 4) = (0, 1, 0)$

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Most popular questions from this chapter

In Exercises 36–41 use the given sets of points to find:

(a) A nonzero vector N perpendicular to the plane determined by the points.

(b) Two unit vectors perpendicular to the plane determined by the points.

(c) The area of the triangle determined by the points.

$P (4, 3, - 2), Q (0, 0, 3), R (- 1, 3, 6)$

What is Lagrange’s identity? How is it used to understand the geometry of the cross product?

Find the norm of the vector. $v = (3, - 4)$

What is a parallelepiped? What is meant by the parallelepiped determined by the vectors u, v and w? How do you find the volume of the parallelepiped determined by u, v and w?

In Exercises 30–35 compute the indicated quantities when $u = (- 3, 1, - 4), v = (2, 0, 5), and w = (1, 3, 13)$

Find the volume of the parallelepiped determined by the vectors u, v, and w.

See all solutions

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