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Chapter 10: Q 6 TB (page 788)

To find the equation of circle in ℝ2having center at (-4, 3) and passing through (5, -2)

Short Answer

Expert verified

The required equation is(x+4)2+(y-3)2=106

Step by step solution

01

Given information

A circle in ℝ2having center at (-4, 3) and passes through (5, -2).

02

Finding the equation

The equation as per the center given is:

(x+4)2+(y-3)2=r2

where ris the radius

Putting the given point in the equation:

(5+4)2+(-2-3)2=r2

Simplifying:

r2=106

The equation of circle is:

(x+4)2+(y-3)2=106

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