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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset Vaia Explanations$ Math

2nd Edition · 1240 pages

ISBN: 9780998625713

Chapter 7: Q. 355 (page 893)

In the following exercises, solve.
$a^{3} - a^{2} - 42 a = 0$

Short Answer

Expert verified

$a = 0, a = 7, a = - 6$

Step by step solution

01

Step 1. Given Information

given expression

$a^{3} - a^{2} - 42 a = 0$

02

Step 2. Calculation

given expression

$a^{3} - a^{2} - 42 a = 0 a (a^{2} - a - 42) = 0 a = 0 a^{2} - a - 42 = 0 a^{2} - 7 a + 6 a - 42 = 0 a (a - 7) + 6 (a - 7) = 0 a = - 6, a = 7$

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