Chapter 7: Q. 356 (page 894)

$4 b^{2} - 60 b + 224 = 0$

Short Answer

Expert verified

$b = 7, b = 8$

Step by step solution

Step 1. Given information

$4 b^{2} - 60 b + 224 = 0$

Step 2. Finding common factor

$4 b^{2} - 60 b + 224 = 0 4 (b^{2} - 15 b + 56) = 0$

Step 3. Divide both sides by same factor

$4 (b^{2} - 15 b + 56) = 0 \frac{4 (b^{2} - 15 b + 56)}{4} = \frac{0}{4} b^{2} - 15 b + 56 = 0$

Step 4. Factorization

$b^{2} - 15 b + 56 = 0 b^{2} - 8 b - 7 b + 56 = 0 b (b - 8) - 7 (b - 8) = 0 (b - 8) (b - 7) = 0$

Step 5. Finding values

$(b - 8) (b - 7) = 0$

So,

$b - 8 = 0 b = 8$

Also,

$b - 7 = 0 b = 7$

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$4 b^{2} - 60 b + 224 = 0$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Finding common factor

Step 3. Divide both sides by same factor

Step 4. Factorization

Step 5. Finding values

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4b2-60b+224=0

Short Answer

Step by step solution

Step 1. Given information

Step 2. Finding common factor

Step 3. Divide both sides by same factor

Step 4. Factorization

Step 5. Finding values

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Theoretical and Mathematical Physics

Logic and Functions

Mechanics Maths

Calculus

Applied Mathematics

Study anywhere. Anytime. Across all devices.

$4 b^{2} - 60 b + 224 = 0$