Factor completely:

7y4-7

Short Answer

Expert verified

The factored form is 7y2+1(y+1)(y-1).

Step by step solution

01

Step 1. Given Information  

We are given a polynomial 7y4-7,

We have to factor the given polynomial.

02

Step 2. Factoring the polynomial  

Factoring out GCF 7, we get

7y4-7=7y4-17y4-7=7y22-12

Using x2-y2=(x+y)(x-y), we get

7y4-7=7y2+1y2-17y4-7=7y2+1y2-12

Again applying difference of square formula, we get

7y4-7=7y2+1(y+1)(y-1)

03

Step 3. Checking the factors  

Using x2-y2=(x+y)(x-y), we get

role="math" localid="1647793519189" 7y2+1(y+1)(y-1)=7y4-77y2+1y2-1=7y4-77y4-1=7y4-77y4-7=7y4-7LHS=RHS

Hence, the factors are correct.

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