Chapter 7: Q. 7.156 (page 887)

Solve: $16 y^{2} = 32 y^{3} + 2 y$

Short Answer

Expert verified

The answer is $y = 0, \frac{1}{4}, \frac{1}{4}$

Step by step solution

Step 1. Given Information.

The given equation is $16 y^{2} = 32 y^{3} + 2 y$ .

Step 2. Factors of the equation.

Bring all the terms to one side:

$32 y^{3} - 16 y^{2} + 2 y = 0$

Factor the greatest common factor,

$2 y (16 y^{2} - 8 y + 1) = 0$

Now, Factor the trinomial,

$2 y (16 y^{2} - 4 y - 4 y + 1) = 0 2 y {4 y (4 y - 1) - 1 (4 y - 1)} = 0 2 y (4 y - 1) (4 y - 1) = 0$

Step 3. Solution of the equation.

On solving,

$2 y = 0, 4 y - 1 = 0, 4 y - 1 = 0 y = 0, y = \frac{1}{4}, y = \frac{1}{4}$

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Solve: $16 y^{2} = 32 y^{3} + 2 y$

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Factors of the equation.

Step 3. Solution of the equation.

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Solve:16y2=32y3+2y

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Factors of the equation.

Step 3. Solution of the equation.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Statistics

Discrete Mathematics

Calculus

Decision Maths

Probability and Statistics

Study anywhere. Anytime. Across all devices.

Solve: $16 y^{2} = 32 y^{3} + 2 y$