Chapter 4: Q. 125 (page 530)

Find an equation of a line containing the points $(- 2, - 4)$ and $(1, - 3)$ .

Short Answer

Expert verified

The equation of the line is $y = \frac{1}{3} x + \frac{14}{3}$ .

Step by step solution

Step 1. Given Information.

The points are:

$(- 2, - 4)$ and $(1, - 3)$ .

Step 2. Finding the Slope.

The slope of the line is,

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Inputting the values,

$m = \frac{- 3 - (- 4)}{1 - (- 2)}$

$= \frac{- 3 + 4}{1 + 2} = \frac{1}{3}$

Step 3. Equation of line

The point-slope form is,

$(y - y_{1}) = m (x - x_{1})$

Inputting the values,

$(y - (- 4)) = \frac{1}{3} (x - (- 2)) y + 4 = \frac{1}{3} (x + 2) y + 4 = \frac{1}{3} x + \frac{2}{3} y = \frac{1}{3} x + \frac{14}{3}$

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Find an equation of a line containing the points $(- 2, - 4)$ and $(1, - 3)$ .

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Finding the Slope.

Step 3. Equation of line

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Find an equation of a line containing the points(-2,-4)and(1,-3).

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Finding the Slope.

Step 3. Equation of line

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Geometry

Pure Maths

Logic and Functions

Discrete Mathematics

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Probability and Statistics

Study anywhere. Anytime. Across all devices.

Find an equation of a line containing the points $(- 2, - 4)$ and $(1, - 3)$ .