In the following exercises, which order pair are solution to the given equation

$2x+y=6$

(a) $(1,4)$(b) $(3,0)$(c)$(2,3)$

We are given an equation : $2x+y=6$and three coordinates : $(1,4),(3,0),(2,3)$we need to find the solution of the given equation

To check if the given coordinate : $(1,4)$we need to put the value of x and y in the equation and see if L.H.S=R.H.S , here we know that x=1 and y = 4

From the equation :$2x+y=6$the R.H.S is 6 need to solve the L.H.S :

$2x+y=2\times 1+4$

$2+4=6$

Therefore, L.H.S=R.H.S so the it is a solution of the equation

To check if the coordinate : $(3,0)$we need to put the value of x and y in the equation and see if L.H.S=R.H.S , here we know that x=3 and y =0

From the equation $2x+y=6$the R.H.S is 6 need to solve the L.H.S :

$2x+y=2\times 3+0$

$6+0=6$

Therefore, L.H.S=R.H.S so the it is a solution of the equation

To check if the coordinate : $(2,3)$we need to put the value of x and y in the equation and see if L.H.S=R.H.S , here we know that x=2 and y =3

From the equation $2x+y=6$the R.H.S is 6 need to solve the L.H.S :

$2x+y=2\times 2+3$

$4+3=7$

Therefore, L.H.S is not equal to R.H.S so it is not the solution to the equation