Plot each point in a rectangular coordinate system and identify the quadrant in which the point is located:

ⓐ $(-2,1)$ ⓑ $(-3,-1)$ ⓒ $(4,-4)$ ⓓ $(-4,4)$ⓔ $(-4,\frac{3}{2})$

The given digits are

$$\begin{gathered} \left(a\right)(-2,1) \\ \left(b\right)(-3,-1) \\ \left(c\right)(4,-4) \\ \left(d\right)(-4,4) \\ \left(e\right)(-4,\frac{3}{2}) \end{gathered}$$

(a) Since $(x=-2)$the point is to the left of the y-axis. Also, since $y=1$, the point is above the x-axis. The point is $(-2,1)$in Quadrant II.

(b)Since $x=-3$, the point is to the left of the $y$-axis. Also, since $y=-1$, the point is below the $x$-axis. The point $(-3,-1)$is in Quadrant III.

(c)Since $x=4$, the point is to the right of the $y$-axis. Since $y=-4$, the point is below the $x$-axis. The point $(4,-4)$is in Quadrant lV.

(d) Since $x=-4$, the point is to the left of the $y$-axis. Since $y=4$, the point is above the $x$-axis. The point $(-4,4)$is in Quadrant II.

(e) Since $x=-4$, the point is to the right of the $y$-axis. Since $y=\frac{3}{2}$, the point is above the $x$-axis. It can be seen that the point$(-4,\frac{3}{2})$is in Quadrant II.

The quadrant that each point is placed using a rectangular coordinate system