Chapter 4: Q. 4.135 (page 536)

Find an equation of a line that is perpendicular to the line $y = 1$ that contains the point $(- 5, 1)$ . Write the equation in slope-intercept form.

Short Answer

Expert verified

The equation of the line that is perpendicular to the line $y = 1$ is $x = - 5$ .

Step by step solution

Step 1. Given data

The given equation of the line is $y = 1$

The point through which the line passes $(- 5, 1)$

Step 2. Equation of the perpendicular line

Here the given line $y = 1$ is a horizontal line.

Therefore any line perpendicular to it will be vertical, in the form $x = a$ .

Since the perpendicular line is vertical and passes through $(- 5, 1)$ , every point on it has an $x$ -coordinate of $- 5$ .

Hence the equation of the perpendicular line is $x = - 5$ .

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Find an equation of a line that is perpendicular to the line $y = 1$ that contains the point $(- 5, 1)$ . Write the equation in slope-intercept form.

Short Answer

Step by step solution

Step 1. Given data

Step 2. Equation of the perpendicular line

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2
-1

Find an equation of a line that is perpendicular to the line y=1that contains the point (−5,1). Write the equation in slope-intercept form.

Short Answer

Step by step solution

Step 1. Given data

Step 2. Equation of the perpendicular line

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Geometry

Discrete Mathematics

Logic and Functions

Applied Mathematics

Probability and Statistics

Study anywhere. Anytime. Across all devices.

Find an equation of a line that is perpendicular to the line $y = 1$ that contains the point $(- 5, 1)$ . Write the equation in slope-intercept form.