Chapter 4: Q. 42 (page 430)

In the following exercises, find three solutions to each linear equation.
$2 x + y = 3$

Short Answer

Expert verified

The three solutions to given linear equation is $(0, 3), (\frac{3}{2}, 0), (1, 1)$

Step by step solution

Step 1. Given information

In the following exercises we have to find three solutions to each linear equation.

$2 x + y = 3$

Step 2. We can substitute any value we want for x or any value for y.

Since the equation is in standard form, let’s pick first $x = 0, then y = 0$ , and then find a third point.

Step 3. Substitute the value into the equation.

$x = 0 y = 0 x = 1 2 x + y = 3 2 x + y = 3 2 x + y = 3 2 \times 0 + y = 3 2 x + 0 = 3 2 \times 1 + y = 3 y = 3 2 x = 3 2 + y = 3 y = 3 \frac{2}{2} x = \frac{3}{2} 2 + y - 2 = 3 - 2 y = 3 x = \frac{3}{2} y = 1$

Step 4. Write the ordered pair.

$(0, 3) (\frac{3}{2}, 0) (1, 1)$

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In the following exercises, find three solutions to each linear equation.
$2 x + y = 3$

Short Answer

Step by step solution

Step 1. Given information

Step 2. We can substitute any value we want for x or any value for y.

Step 3. Substitute the value into the equation.

Step 4. Write the ordered pair.

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In the following exercises, find three solutions to each linear equation.2x+y=3

Short Answer

Step by step solution

Step 1. Given information

Step 2. We can substitute any value we want for x or any value for y.

Step 3. Substitute the value into the equation.

Step 4. Write the ordered pair.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Mechanics Maths

Pure Maths

Statistics

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Probability and Statistics

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Study anywhere. Anytime. Across all devices.

In the following exercises, find three solutions to each linear equation.
$2 x + y = 3$