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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset Vaia Explanations$ Math

2nd Edition · 1240 pages

ISBN: 9780998625713

Chapter 4: Q. 450 (page 539)

find the equation of a line containing the points (-2,-3) and (-5,-6) .Write the equation in slope–intercept form.

Short Answer

Expert verified

Equation of the line is y=x-1

Step by step solution

01

Step 1. Given information

Two points are (-2,-3) and (-5,-6)

02

Step 2. Equation of the line

Slope of the line is

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} m = \frac{- 6 - (- 3)}{- 5 - (- 2)} = 1$

Equation of the line passes through (-2,-3) and slope =1 is

$(y - y_{1}) = m (x - x_{1}) y + 3 = 1 (x + 2) y = x - 1$

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Most popular questions from this chapter

In the following exercises, plot each point in a rectangular coordinate system.

ⓐ $(- 2, 0)$ ⓑ $(- 3, 0)$ ⓒ $(0, 0)$ ⓓ $(0, 4)$ ⓔ $(0, 2)$

Name the ordered pair of each point shown in the rectangular coordinate system.

Find the intercepts for $x - y = - 3$

In the following exercises, plot each point in a rectangular coordinate system and identify the quadrant in which the point is located.

ⓐ $(- 1, 1)$ ⓑ $(- 2, - 1)$ ⓒ $(2, 1)$ ⓓ $(1, - 4)$ ⓔ $(3, \frac{7}{2})$

In the following exercises, complete the table to find solutions to each linear equation.

See all solutions

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