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Elementary Algebra

Lynn Marecek, MaryAnne Anthony-Smith

$Math Studyset Vaia Explanations$ Math

2nd Edition · 1240 pages

ISBN: 9780998625713

Chapter 4: Q. 451 (page 539)

find the equation of a line containing the points (-3,0) and (-7,-2) .Write the equation in slope–intercept form.

Short Answer

Expert verified

Equation of the line is $y = \frac{x}{2} + \frac{3}{2}$

Step by step solution

01

Step 1. Given information

Two points are (-3,0) and (-7,-2)

02

Step 2. Equation of the line

Slope of the line is

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} m = \frac{- 2 - 0}{- 7 - (- 3)} = \frac{1}{2}$

Equation of the line passes through (-3,0) and slope = $\frac{1}{2}$ is

$(y - y_{1}) = m (x - x_{1}) y - 0 = \frac{1}{2} (x + 3) y = \frac{x}{2} + \frac{3}{2}$

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Most popular questions from this chapter

Find three solutions to this equation: $y = - 2 x + 3 .$

In the following exercises, complete the table to find solutions to each linear equation.

In the following exercises, which ordered pairs are solutions to the given equations :

$y = \frac{1}{2} x - 1$

(a) $(2, 0)$ (b) $(- 6, - 4)$ (c) $(- 4, - 1)$

In the following exercises, which ordered pairs are solutions to the given equations :

$y = \frac{1}{3} x + 1$

(a) $(- 3, 0)$ (b) $(9, 4)$ (c) $(- 6, - 1)$

In the following exercises, which ordered pairs are solutions to the given equation :

$y = 4 x + 3$

(a) $(4, 3)$ (b) $(- 1, - 1)$ (c) $(\frac{1}{2}, 5)$

See all solutions

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