Chapter 3: Q. 161 (page 351)

Jaime has $ $2.60$ in dimes and nickels. The number of dimes is 14 more than the number of nickels. How many of each coin does he have?

Short Answer

Expert verified

The number of nickels are $8$ and dimes are $22$ .

Step by step solution

Step 1. Assumption Of variables

Let he number of nickels be $x$

Therefore ,

According to the question,

number of dimes will be $14 + x$

Value of each dime $= 0.10$

The total value of dimes will be $0.10 (x + 14)$

Value of each nickel is $0.05$

Therefore, total value of nickels will be $0.05 x$

Step 2. Solution of the equation

Now, According to the question,

$0.10 (x + 14) + 0.05 x = 2.60 0.10 x + 1.4 + 0.05 x = 2.60 0.15 x + 1.4 = 2.60 0.15 x = 2.60 - 1.4 \frac{0.15 x}{0.15} = \frac{1.2}{0.15} x = 8 14 + x = 14 + 8 = 22$

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Jaime has $ $2.60$ in dimes and nickels. The number of dimes is 14 more than the number of nickels. How many of each coin does he have?

Short Answer

Step by step solution

Step 1. Assumption Of variables

Step 2. Solution of the equation

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Jaime has $2.60in dimes and nickels. The number of dimes is 14 more than the number of nickels. How many of each coin does he have?

Short Answer

Step by step solution

Step 1. Assumption Of variables

Step 2. Solution of the equation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Discrete Mathematics

Applied Mathematics

Logic and Functions

Decision Maths

Pure Maths

Study anywhere. Anytime. Across all devices.

Jaime has $ $2.60$ in dimes and nickels. The number of dimes is 14 more than the number of nickels. How many of each coin does he have?