Chapter 3: Q. 162 (page 351)

Lee has $ $1.75$ in dimes and nickels. The number of nickels is $11$ more than the number of dimes. How many of each coin does he have?

Short Answer

Expert verified

The number of dimes is $8$ and number of nickels is $19$

Step by step solution

Step 1. Given Information

Total amount of money $= $ 1.75$

Let he number of dimes be $x$

Therefore ,

According to the question,

number of nickels will be $11 + x$

Step 2. Solution of the equation

Value of each dime $0.10$

Value of each nickel is $0.05$

Now, According to the question,

$0.10 x + 0.05 (x + 11) = 1.75 0.10 x + 0.05 x + 0.55 = 1.75 0.15 x + 0.55 = 1.75 0.15 x = 1.2 \frac{0.15 x}{0.15} = \frac{1.2}{0.15} x = 8 11 + x = 11 + 8 = 19 .$

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Lee has $ $1.75$ in dimes and nickels. The number of nickels is $11$ more than the number of dimes. How many of each coin does he have?

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solution of the equation

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Lee has $1.75 in dimes and nickels. The number of nickels is 11 more than the number of dimes. How many of each coin does he have?

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solution of the equation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Decision Maths

Pure Maths

Geometry

Discrete Mathematics

Logic and Functions

Study anywhere. Anytime. Across all devices.

Lee has $ $1.75$ in dimes and nickels. The number of nickels is $11$ more than the number of dimes. How many of each coin does he have?