Chapter 3: Q. 171 (page 351)

In a cash drawer there is $ $125$ in $ $5$ and $ $10$ bills. The number of $ $10$ bills is twice the number of $ $5$ bills. How many of each are in the drawer?

Short Answer

Expert verified

The number of $$ 5$ bill is $5$ and number of $$ 10$ bill is $10 .$

Step by step solution

Step 1. Given Information

Total amount of money $= $ 125$

Let he number of $$ 5$ bills be $x$

Therefore ,

According to the question,

number of $$ 10$ bills will be $2 x$

Step 2. Solution of the equation

Now, According to the question,

$20 x + 5 x = 125 25 x = 125 \frac{25 x}{25} = \frac{125}{25} x = 5 T h e r e f o r e, 2 x = 10$

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In a cash drawer there is \( $125$ in \) $5$ and \( $10$ bills. The number of \) $10$ bills is twice the number of $ $5$ bills. How many of each are in the drawer?

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solution of the equation

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In a cash drawer there is \(125in \)5and \(10bills. The number of \)10 bills is twice the number of $5 bills. How many of each are in the drawer?

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solution of the equation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Geometry

Decision Maths

Applied Mathematics

Mechanics Maths

Calculus

Study anywhere. Anytime. Across all devices.

In a cash drawer there is \( $125$ in \) $5$ and \( $10$ bills. The number of \) $10$ bills is twice the number of $ $5$ bills. How many of each are in the drawer?