Chapter 3: Q. 176 (page 351)

Tyler has $$ 9.70$ in dimes and quarters. The number of quarters is eight more than four times the number of dimes. How many of each coin does he have?

Short Answer

Expert verified

The number of quarters is $36$ and number of dimes is $7$ .

Step by step solution

Step 1. Given Information

Total Amount $= $ 9.70$

Number of quarters is eight more than four times the number of dimes.

Step 2. Naming the variables

Let the number of dimes be $x$ .

We know, number of quarters = $4 \times$ number of dimes $+ 8$

Therefore, number of quarters $= 4 x + 8$

Step 3. Creating the table

The required table is

Step 4. Solving the equation

Translating into equation we get,

$0.10 x + 0.25 (4 x + 8) = 9.70 \Rightarrow 0.10 x + x + 2 = 9.70 \Rightarrow 1.10 x = 9.70 - 2 \Rightarrow 1.10 x = 7.70 \Rightarrow x = \frac{7.70}{1.10} \Rightarrow x = 7 ∴ 4 x + 8 = 4 (7) + 8 \Rightarrow 4 x + 8 = 28 + 8 \Rightarrow 4 x + 8 = 36$

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Tyler has $$ 9.70$ in dimes and quarters. The number of quarters is eight more than four times the number of dimes. How many of each coin does he have?

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Naming the variables

Step 3. Creating the table

Step 4. Solving the equation

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Tyler has $9.70in dimes and quarters. The number of quarters is eight more than four times the number of dimes. How many of each coin does he have?

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Naming the variables

Step 3. Creating the table

Step 4. Solving the equation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Theoretical and Mathematical Physics

Pure Maths

Calculus

Probability and Statistics

Geometry

Study anywhere. Anytime. Across all devices.

Tyler has $$ 9.70$ in dimes and quarters. The number of quarters is eight more than four times the number of dimes. How many of each coin does he have?