Scott has $\$0.39$ in pennies and nickels. The number of pennies is eight times the number of nickels. How many of each coin does he have?

The number of pennies is eight times the number of nickels and Scott has $\$0.39$ in pennies and nickels. We have to find the number of coins he has.

Let xbe the number of nickel.

Now, the number of pennies is eight times the number of nickels.

So, the number of pennies $=8x$

The value of pennies in the dollar is $0.01$and the value of nickels in the dollar is $0.05.$

Thus, the table is

The total value of pennies and nickels is $\$0.39.$

Write the equation by adding the total value of all the types of coins.

So,$\left(0.05\right)x+\left(0.01\right)8x=0.39$

By proceeding with the equation we get,

$$\begin{gathered} \left(0.05\right)x+\left(0.01\right)8x=0.39 \\ 0.05x+0.08x=0.39 \\ 0.13x=0.39 \\ x=3 \end{gathered}$$

So, there are$3$nickels and pennies$8\left(3\right)=24$

To check the answer replace xby $3$into the original equation.

$$\begin{gathered} 0.05\left(3\right)+0.01\left(8\left(3\right)\right)=0.39 \\ 0.15+0.24=0.39 \\ 0.39=0.39 \end{gathered}$$

It is true.

Therefore, the number of nickels is $3$and pennies is$24.$