Chapter 3: Q. 440 (page 411)

The length of a rectangle is two feet more than five times the width. The perimeter is $40$ feet. Find the dimensions of the rectangle.

Short Answer

Expert verified

The length of the rectangle is $17$ feet and width is $3$ feet.

Step by step solution

Step 1. Given Information

Length of a rectangle is two feet more than five times the width.

Perimeter of the rectangle $= 40$ feet

Step 2. Finding the dimensions

Let the width of the reactangle be $x$ .

Therefore, length $= 2 + 5 x$

We know, perimeter of the rectangle $= 2 (length + width)$

localid="1655808249195" $∴ 2 (2 + 5 x + x) = 40 \Rightarrow 2 (2 + 6 x) = 40 \Rightarrow (2 + 6 x) = \frac{40}{2} \Rightarrow (2 + 6 x) = 20 \Rightarrow 6 x = 20 - 2 \Rightarrow 6 x = 18 \Rightarrow x = \frac{18}{6} \Rightarrow x = 3 ∴ (2 + 5 x) = 2 + 5 (3) \Rightarrow (2 + 5 x) = 2 + 15 \Rightarrow (2 + 5 x) = 17$

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The length of a rectangle is two feet more than five times the width. The perimeter is $40$ feet. Find the dimensions of the rectangle.

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Finding the dimensions

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The length of a rectangle is two feet more than five times the width. The perimeter is 40feet. Find the dimensions of the rectangle.

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Finding the dimensions

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Geometry

Calculus

Discrete Mathematics

Mechanics Maths

Probability and Statistics

Study anywhere. Anytime. Across all devices.

The length of a rectangle is two feet more than five times the width. The perimeter is $40$ feet. Find the dimensions of the rectangle.