Chapter 6: Q. 769 (page 806)

In the following exercises, simplify each expression.
${(87 x^{15} y^{3} z^{22})}^{0}$ .

Short Answer

Expert verified

The simplified expression for ${(87 x^{15} y^{3} z^{22})}^{0}$ is, $1$ .

Step by step solution

Step 1. Given information

${(87 x^{15} y^{3} z^{22})}^{0}$ .

We need to simplify the given expression.

Step 2. Use the product to a power property in the given expression.

${(a b)}^{m} = a^{m} b^{m}$ .

${(87 x^{15} y^{3} z^{22})}^{0} = {(87)}^{0} {(x^{15})}^{0} {(y^{3})}^{0} {(z^{22})}^{0}$

Use the Power property, ${(a^{m})}^{n} = a^{m . n}$ .

${(87)}^{0} {(x^{15})}^{0} {(y^{3})}^{0} {(z^{22})}^{0} = (87^{0}) (x^{15.0}) (y^{3.0}) (z^{22.0}) = (87^{0}) (x^{0}) (y^{0}) (z^{0})$

Now simplify it.

$(87^{0}) (x^{0}) (y^{0}) (z^{0}) = 1.1.1.1 = 1$

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In the following exercises, simplify each expression.
${(87 x^{15} y^{3} z^{22})}^{0}$ .

Short Answer

Step by step solution

Step 1. Given information

Step 2. Use the product to a power property in the given expression.

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In the following exercises, simplify each expression.87x15y3z220.

Short Answer

Step by step solution

Step 1. Given information

Step 2. Use the product to a power property in the given expression.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Geometry

Probability and Statistics

Applied Mathematics

Statistics

Mechanics Maths

Study anywhere. Anytime. Across all devices.

In the following exercises, simplify each expression.
${(87 x^{15} y^{3} z^{22})}^{0}$ .