Chapter 6: Q. 80 (page 698)

Stopping Distance The number of feet it takes for a car traveling at x miles per hour to stop on dry, level concrete is given by the polynomial $0.06 x^{2} + 1.1 x$ . Find the stopping distance when $x = 40$ mph.

Short Answer

Expert verified

The stopping distance when $x = 40$ mph is 140 feet.

Step by step solution

Step 1. Given information.

The number of feet it takes for a car traveling at x miles per hour to stop on dry, level concrete is:

$0.06 x^{2} + 1.1 x$

The speed of car is $x = 40$ mph.

Step 2. Evaluate the expression for the given value.

Substitute $x = 40$ in the given expression.

$\begin{array}{rcl} 0.06 (40)^{2} + 1.1 (40) & = & 0.06 (1600) + 44 \\ = & 96 + 44 \\ = & 140 \end{array}$

Step 3. Conclusion.

The stopping distance when $x = 40$ mph is 140 feet.

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Stopping Distance The number of feet it takes for a car traveling at x miles per hour to stop on dry, level concrete is given by the polynomial $0.06 x^{2} + 1.1 x$ . Find the stopping distance when $x = 40$ mph.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Evaluate the expression for the given value.

Step 3. Conclusion.

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Stopping Distance The number of feet it takes for a car traveling at x miles per hour to stop on dry, level concrete is given by the polynomial 0.06x2+1.1x. Find the stopping distance whenx=40 mph.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Evaluate the expression for the given value.

Step 3. Conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Geometry

Calculus

Probability and Statistics

Pure Maths

Discrete Mathematics

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

Stopping Distance The number of feet it takes for a car traveling at x miles per hour to stop on dry, level concrete is given by the polynomial $0.06 x^{2} + 1.1 x$ . Find the stopping distance when $x = 40$ mph.