Chapter 6: Q. 82 (page 698)

Height of Projectile The height (in feet) of an object projected upward is given by the polynomial $- 16 t^{2} + 60 t + 90$ wheret represents time in seconds. Find the height after $t = 2.5$ seconds.

Short Answer

Expert verified

The height of the object after $t = 2.5$ seconds is 140 feet.

Step by step solution

Step 1. Given information.

The height (in feet) of an object after t seconds is:

$- 16 t^{2} + 60 t + 90$

The given time is $t = 2.5$ seconds.

Step 2. Evaluate the expression for the given value.

Substitute $t = 2.5$ in the given expression.

$\begin{array}{rcl} - 16 (2.5)^{2} + 60 (2.5) + 90 & = & - 16 (6.25) + 150 + 90 \\ = & - 100 + 240 \\ = & 140 \end{array}$

Step 3. Conclusion.

The height of the object after $t = 2.5$ seconds is 140 feet.

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Height of Projectile The height (in feet) of an object projected upward is given by the polynomial $- 16 t^{2} + 60 t + 90$ wheret represents time in seconds. Find the height after $t = 2.5$ seconds.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Evaluate the expression for the given value.

Step 3. Conclusion.

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Height of Projectile The height (in feet) of an object projected upward is given by the polynomial −16t2+60t+90wheret represents time in seconds. Find the height after t=2.5seconds.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Evaluate the expression for the given value.

Step 3. Conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Geometry

Statistics

Probability and Statistics

Discrete Mathematics

Calculus

Mechanics Maths

Study anywhere. Anytime. Across all devices.

Height of Projectile The height (in feet) of an object projected upward is given by the polynomial $- 16 t^{2} + 60 t + 90$ wheret represents time in seconds. Find the height after $t = 2.5$ seconds.